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# Tutor profile: Aman M.

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Aman M.
Student at Wake Forest University
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## Questions

### Subject:Pre-Calculus

TutorMe
Question:

Solve the following equation: ln(x) + ln(x+2) = ln(x+6).

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Aman M.

ln(x) + ln(x+2) = ln(x+6) --> ln(x(x+2)) = ln(x+6) --> x(x+2) = x+6 --> (x^2)+2x = x+6 --> (x^2)+x-6=0 --> (x+3) (x-2) = 0 --> x = -3 or x = 2 --> x = -3 does not exist in original equation, therefore only answer is x = 2.

### Subject:Writing

TutorMe
Question:

What types of questions can be asked pertaining to writing?

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Aman M.

I assume that any typical writing question will pertain to diction, grammar, and structure - all of which can be resolved through careful analysis of the clauses in question and use basic techniques used by the most successful of writers.

### Subject:Chemistry

TutorMe
Question:

What is the molarity of a solution containing 9.569 grams of RuCl3 in enough water to create a 1.00 L solution?

Inactive
Aman M.

First, recall that moles = concentration x volume. Molarity equates to concentration. We can isolate molarity (concentration) by rearranging the equation to give the following: concentration = moles/volume. Now we know that we have 9.569 grams of RuCl3, and using the molar mass of the compound, we can calculate the moles of RuCl3 being used to be 0.046 moles. The volume of the entire solution will be 1.00 L. Inserting our known values into the molarity equation gives us 0.046 moles / 1.00 L = 0.046 M as the molarity of the final solution.

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