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Tutor profile: Lauren L.

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Lauren L.
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Questions

Subject: Pre-Calculus

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Question:

Given 4pi/11, what quadrant does the angle fall in, and what is its supplementary angle?

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Lauren L.
Answer:

Seeing that 4pi/11 is a positive angle and 4/11 is less than half, (meaning it will be less than 90 degrees) we know that the angle will fall in the 1st quadrant. The supplementary angle of a given angle is a degree or radian whose sum with the given value will be 180 degrees or pi. Seeing that the denominator of 11, we know that pi for this equation can be written as 11pi/11. Therefore, this can be written as x + 4 = 11 which x being the missing numerator of the supplementary angle (x pi/11). Thus the answer will be 7pi/11.

Subject: Basic Math

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Question:

Solve the following word expression: Six plus eight divided by four times forty-two minus eight

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Lauren L.
Answer:

Looking at this problem, we need to remember the order that we must carry out functions, popularly known as PEMDAS. Knowing this, we will first carry out eight divided by four which equals two -- turning the problem into Six plus two times forty-two minus eight. The next step is to multiple two times forty-two, which is eighty-four -- turning the problem into Six plus eighty-four minus eight. Finally, carrying out the last addition and subtraction steps, the final answer would be eighty-two.

Subject: Basic Chemistry

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Question:

Given the reaction Na2SO3 + 2HCl = NaCl + H2O + SO2, how many grams of SO2 can be produced when given 3.6 g of NaSO3?

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Lauren L.
Answer:

We first start out by recording the given values which are 3.6 g of Na2SO3 and the reaction stated above. We must also identify that "g of SO2" is the unknown, aka what we are looking for. Looking at the given and knowing that we must find grams of SO2 produced, we can see that this is a stoichiometry problem -- therefore we must also find the molar mass of Na2SO3 (126.043 g/mol) and SO2(64.066 g/mol). We will now set up the paper for a conversion using the mole to mole ratio of Na2SO3 and SO2 from the chemical reaction. (3.6g of Na2SO3)*(1 mole of Na2SO3/126.043 g of Na2SO3)*(1 mole of SO2/1 mole of Na2SO3)*(64.066 g of SO2/1 mole of SO2) From the expression above, common units diagonally cancel out leaving us with the final unit of "g of SO2" which is the unknown of the problem indicated at the beginning. The final raw answer will be 1.8298 g of SO2. Though this may be correct, we must look at the sig figs of the problem and identify that there should only be 2 due to the given of 3.6 g. So the final answer will be rounded to 1.8 g of SO2.

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