Enable contrast version

# Tutor profile: Stephanie O.

Inactive
Stephanie O.
Fourth Year Chemical Engineering Student at UofT
Tutor Satisfaction Guarantee

## Questions

### Subject:Calculus

TutorMe
Question:

Find the derivative of the following function: f(x) = x^2 + 2x^5 + 20

Inactive
Stephanie O.

1. Use the chain rule, where: if f(x) = x^n (where n is any constant), then the derivative f'(x) = n*x^(n-1) 2. solve for the derivative, f'(x) by taking the derivative of each term in f(x) f'(x) = 2x + 10x^4 **Remember that the derivative of a constant equals 0

### Subject:English

TutorMe
Question:

Identify the subject and the predicate in the following sentences: 1. The sun was shining brightly. 2. The dogs were barking loudly. 3. The pretty girl was wearing a blue frock. 4. My younger brother serves in the army. 5. The man and his wife were working in their garden. 6. My mother and my aunt are trained classical dancers. 7. You don’t have to wait for me. 8. We will no longer tolerate this. 9. The little tree was covered with needles instead of leaves. 10. A rich merchant was passing by the shoemaker’s window.

Inactive
Stephanie O.

1. The sun (subject) / was shining brightly (predicate). 2. The dogs (subject) / were barking loudly (predicate). 3. The pretty girl (subject) / was wearing a blue frock (predicate). 4. My younger brother (subject) / serves in the army (predicate). 5. The man and his wife (subject) / were working in their garden (predicate). 6. My mother and my aunt (subject) / are trained classical dancers (predicate). 7. You (subject) / don’t have to wait for me (predicate). 8. We (subject) / will no longer tolerate this (predicate). 9. The little tree (subject) / was covered with needles instead of leaves (predicate). 10. A rich merchant (subject) /was passing by the shoemaker’s window (predicate).

### Subject:Algebra

TutorMe
Question:

Solve for X: 10x + 2(x+7) = 20x + 5

Inactive
Stephanie O.

1. Begin by simplifying the expression and expanding the "2(x+7)" term: 2(x+7) ---> 2x + 14 2. Rewrite the original expression with the expanded "2(x+7)" term: 10x + 2(x+7) = 20x + 5 10x + 2x + 14 = 20x + 5 3. Combine like terms on both sides: 12x + 14 = 20x + 5 4. Get all the x's on one side and the constant terms on the other by adding/subtracting: 12x + 14 = 20x + 5 ---> *subtract 12x from both sides* 12x - 12x + 14 = 20x - 12x + 5 14 = 8x + 5 ---> subtract 5 from both sides 14 - 5 = 8x + 5 - 5 9 = 8x 5. Divide both sides by 8 to isolate (solve for) x: x = 9/8

## Contact tutor

Send a message explaining your
needs and Stephanie will reply soon.
Contact Stephanie

Start Lesson

## FAQs

What is a lesson?
A lesson is virtual lesson space on our platform where you and a tutor can communicate. You'll have the option to communicate using video/audio as well as text chat. You can also upload documents, edit papers in real time and use our cutting-edge virtual whiteboard.
How do I begin a lesson?
If the tutor is currently online, you can click the "Start Lesson" button above. If they are offline, you can always send them a message to schedule a lesson.
Who are TutorMe tutors?
Many of our tutors are current college students or recent graduates of top-tier universities like MIT, Harvard and USC. TutorMe has thousands of top-quality tutors available to work with you.
BEST IN CLASS SINCE 2015
TutorMe homepage