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Jeffrey W.

Tutor from Utah State University/Programmer

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Geometry

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Question:

Given a triangle with angles of 30 degrees and 40 degrees determine if the triangle is a right triangle.

Jeffrey W.

Answer:

Given the information above we can determine the third angle. We know a right triangle has an angle that is 90 degrees. All three angles of triangles must equal 180 degrees. So we can find the third angle with the following equation. 180-30-40=the third angle. Doing the subtraction we find that the third angle equals 110 degrees. Since 110 degrees is not 90 degrees we know that the triangle is not a right triangle.

C++ Programming

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Question:

what will y equal after the following code has been executed? int y=4; for(int x=0;x<10;x++) { y=x+y; }

Jeffrey W.

Answer:

To begin with y is initialized to 4. The loop will be executed 10 times once as 0,1,2,3,4,5,6,7,8 and 9. y always adds its previous value to the current value of x. So the first time the loop is executed y=0+4 which gives 4. The second time through the loop you get y=1+4 which gives 5. The third time through the loop you get y=2+5 which gives 7. You continue this pattern to get y=7+3+4+5+6+7+8+9 which gives 49. So y=49 once the code has finished executing.

Algebra

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Question:

Solve for x: x^2+8x+12=0

Jeffrey W.

Answer:

Two numbers that when times together equal 12 (coefficient of first term times coefficient of third term) but add together to equal 8 (coefficient of second term) are 6 and 2. Knowing this we can break down the equation x^2+8x+12=0 to become (x+6)(x+2)=0 Then since anything times anything equals zero you can break it into two equations (x+6)=0 and (x+2)=0. You can subtract 6 from both the right hand side and left hand side of first equation to get x=-6. You can subtract 2 from both sides of second equation to get x=-2. So x=-6 or -2

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