Find the derivative of 3x^2
This is simple power rule, so multiple the coefficient (3) by the exponent (2) to get the new coefficient (6), and subtract 1 from the degree of the exponent (currently 2, now 1) to get the derivative: 6x.
3x+1=15, solve for x
3x+1=15 3x= 14 (subtract the 1 from 15) x= 14/3 (divide the 3 from x and from 14)
What is the coordinates of the vertex of the parabola with equation x^2 + 2x + 1 = 0?
Vertex of parabola is equivalent to x= -b/2a in a binomial with equation ax^2+bx+c=0. Thus, (-2)/(2)(1) = -1. This represents the x-coordinate of the vertex of the parabola. If you plug in -1 into the equation, you will be able to find the y-coordinate of the vertex. A vertex is simply the minimum point of an upward facing parabola, or it is the maximum point when the parabola is faced-downwards. Understanding this helps with problems that involve graphing.